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A bus moving at a speed of 45km/hour overtakes a truck 150 m ahead going in the same direction in 30sec.The sp?

  • A bus moving at a speed of 45km/hour overtakes a truck 150 m ahead going in the same direction in 30sec.The speed of the truck is?


  • Let x = speed of the truck

    Bus travels:
    D = rt
    r = 45km/hr
    t = 30s

    D = (45km/hr)(30s)(1000m/km)(1hr/3600s)

    D = 375 m


    Truck:
    The truck travels 150 m less than the bus:
    D = 375 - 150

    D = 225 m

    D = rt

    225 m = r(30s)

    225/30 m/s = r

    r = 7.5 m/s

    r = (7.5 m/s)(3600s/hr)(1km/1000m) = 27 km/hr


  • speed = distance/time

    distance=150m

    time=30 sec

    speed= speed of the bus-speed of the truck[ since they are going in the same direction]

    speed=45-x

    45-x=150/3
    45km/hr-x=50m/sec

    162 m/sec-x=50m/sec

    speed of the truck=112m/sec





  • Let x be the speed of the truck...
    First we will convert everything into meters per second...

    45km = 45000m
    1 hr = 3600 seconds
    45000m/3600 seconds = 12.5m/second
    Now we create the relation:

    30*12.5 = 30*x + 150
    375 = 30x + 150
    225 = 30x
    x = 7.5
    Therefore, the truck is moving at 7.5 meters per second, which is (x3600 seconds / 1000 m) = 27km/hr







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